X:= CharPack("The quick brown fox jumped over the lazy dog." )
"Packed string: " , x ---------------------> "The quick brown fox jumped 
over the lazy dog."
 "Unpacked string: " ,CharUnPack(x) ---------------------> "The quick brown 
fox jumped over the lazy dog."

Both functions return the same string?  Ie. The Charpack function does not 
pack the string?

Am I not using the function (s) correctly?

Jim Graham
Vice President
Professional Teledata
175 Canal Street
Manchester, NH 03101
800.344.9944
www.proteledata.com

Hi Jim,

Don't remember seeing CharPack() before and would assume it is supposed to
remove at least the spaces from the string being packed.  Won't hazard a
guess as to what CharUnPack() is supposed to do.

I've always used CharRem() and it works as advertised.

Ain't computers fun?!

   >don<

On Thu, 11 Sep 2008 10:06:00 -0400, Jim Graham wrote:

>  X:= CharPack("The quick brown fox jumped over the lazy dog." )
> "Packed string: " , x ---------------------> "The quick brown fox jumped 
> over the lazy dog."
>  "Unpacked string: " ,CharUnPack(x) ---------------------> "The quick
brown 
> fox jumped over the lazy dog."
> 
> Both functions return the same string?  Ie. The Charpack function does
not 
> pack the string?
> 
> Am I not using the function (s) correctly?

Hello Jim,

> X:= CharPack("The quick brown fox jumped over the lazy dog." )
> "Packed string: " , x ---------------------> "The quick brown fox
> jumped
> over the lazy dog."
> "Unpacked string: " ,CharUnPack(x) ---------------------> "The quick
> brown
> fox jumped over the lazy dog."
> Both functions return the same string?  Ie. The Charpack function does
> not pack the string?
> 
> Am I not using the function (s) correctly?

What is your goal?  Your sample string does not lend itself to run-length 
encoding since it does not have any character runs.

You will see CharPack() do something if you submit a string like "aaaaabbbbbbbcccccc" 
which has character runs.

It is difficult to get compression out of short data sequences due to the 
need for redundancy and the overhead of representing compression metadata.

Regards,

Rodd Graham, Consultant
Graham Automation Systems, LLC