Hello to all

I cannot understand that it happens with this example, if the mistake is 
mine or of xbase

When I load the array in the 2nd FOR, it me loads the remaining elements

please, can you helpme ?

thanks and regards

Hi

If i initialize the array with afill( aaux, {} ), the content of all the 
subarray, they are unified, surely for the managing for reference of the 
variable

But if i initialize with a for - next, i don't have problems, the behavior 
of every subarray is independent

Regards


"Jorge L"  escribió en el mensaje de 
noticias:5135ce10$1126e3f0$3a68f@news.alaska-software.com...

Hello to all

I cannot understand that it happens with this example, if the mistake is
mine or of xbase

When I load the array in the 2nd FOR, it me loads the remaining elements

please, can you helpme ?

thanks and regards

On Mon, 29 Oct 2012 12:00:19 -0300, Jorge L wrote:

> Hi
> 
> If i initialize the array with afill( aaux, {} ), the content of all the 
> subarray, they are unified, surely for the managing for reference of the 
> variable
> 
> But if i initialize with a for - next, i don't have problems, the behavior 
> of every subarray is independent
> 
> Regards
> 
> "Jorge L"  escribió en el mensaje de 
> noticias:5135ce10$1126e3f0$3a68f@news.alaska-software.com...
> 
> Hello to all
> 
> I cannot understand that it happens with this example, if the mistake is
> mine or of xbase
> 
> When I load the array in the 2nd FOR, it me loads the remaining elements
> 
> please, can you helpme ?
> 
> thanks and regards

Jorge,

Initialize the array with the following:
aAux := Array(8,0)

That will resolve all of your issues.

If you use aFill(...,{}) it will point all elements to the same
section of memory.

By using array(8,0) it knows to create a new block of memory for each
sub element of the array.

Thank you richard !

"Richard Hankins" escribió en el mensaje de 
noticias:1qzuxamoa0h3p.1l6832nz5nuvj.dlg@40tude.net...

On Mon, 29 Oct 2012 12:00:19 -0300, Jorge L wrote:

> Hi
>
> If i initialize the array with afill( aaux, {} ), the content of all the
> subarray, they are unified, surely for the managing for reference of the
> variable
>
> But if i initialize with a for - next, i don't have problems, the behavior
> of every subarray is independent
>
> Regards
>
> "Jorge L"  escribió en el mensaje de
> noticias:5135ce10$1126e3f0$3a68f@news.alaska-software.com...
>
> Hello to all
>
> I cannot understand that it happens with this example, if the mistake is
> mine or of xbase
>
> When I load the array in the 2nd FOR, it me loads the remaining elements
>
> please, can you helpme ?
>
> thanks and regards

Jorge,

Initialize the array with the following:
aAux := Array(8,0)

That will resolve all of your issues.

If you use aFill(...,{}) it will point all elements to the same
section of memory.

By using array(8,0) it knows to create a new block of memory for each
sub element of the array.

Jorge L wrote:

> Hi
> 
> If i initialize the array with afill( aaux, {} ), 

Think of afill like this:

FUNCTION afill( aArray, xValue )
LOCAL nI

FOR nI := 1 TO LEN(aArray)
   aArray[nI] := xValue
NEXT

RETURN aArray

This is why every element of aaux holds the same reference to the empty
array {}

Use either the method Richard wrote or your own for...next loop

Thomas